Question

4.i and m are two parallel lines intersected by another pair of parallel lines p and q (see fig. 7.19). show that . delta abc cong triangle cda fig. 7.18 a​

Answer 1

In △ABC and △CDA

∠BAC=∠DCA (Alternate interior angles, as p∥q)

AC=CA (Common)

∠BCA=∠DAC (Alternate interior angles, as l∥m)

∴△ABC≅△CDA (By ASA congruence rule)

Answer 2

Step-by-step explanation:

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Solution:

It is given that p q and l m

To prove:

Triangles ABC and CDA are similar i.e. ΔABC ΔCDA

Proof:

Consider the ΔABC and ΔCDA,

(i) BCA = DAC and BAC = DCA Since they are alternate interior angles

(ii) AC = CA as it is the common arm

So, by ASA congruency criterion, triangle ABC triangle CDA.

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