4. (i) Find the 10th term of the AP whose first term is 7 and common difference is 3.
(i) Find the 105th term of the AP whose first term is 2.7 and common difference is 0.
Answers
Answered by
3
Answer:
1)Ans=34
Step-by-step explanation:
tn=a+(n-1)d
t10=7+(10-1)3
=7+(9)3
=7+27
=34
Answered by
0
Given:
1. First term = 7 and second term = 3
2. First term = 2.7 and second = 0
To find:
1. 10th term
2. 105th term
Solution:
1. The first term a = 7
Then, common difference d =3
Tn = a + ( n - 1)d
Thus,
T10 = a + ( 10 - 1)d
= 7 + (10−1) 3
=7 + (9) 3
= 7+ 27
= 34
2. The first term a = 2.7
Then, common difference d = 0
Tn = a + ( n - 1)d
Thus,
T105 = a + ( 105 - 1)d
= 2.7 + (105 −1) 0
= 2.7 + ( 104 )0
= 2.7 + 0
= 2.7
Answer: The 10th term is 34 and the 105th term is 2.7
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