Question

4. (i) x2 = x + 3y x - 3y find derivative ​

Answer 1

Answer:

The Answer is here

Solution:

x

2

=

x−3y

x+3y

CrossingMultiplying:

x

2

(x−3y)=(x+3y)

x

3

−3x

2

y=x+3y

x

3

−3x

2

y−x−3y=0

Now,DifferentiateBothSideswrtx:

3x

2

−(3x

2

dx

dy

+y

dx

d

×3x

2

)−1−3

dx

dy

=0

3x

2

−3x

2

dx

dy

−y(6x)−1−3

dx

dy

=0

Taking

dx

dy

Common:

dx

dy

(−3x

2

−3)−6xy+3x

2

−1=0

dx

dy

(−3x

2

−3)=6xy+3x

2

−1=0

−3(x

2

+1)

dx

dy

=6xy−3x

2

+1

3(x

2

+1)

dx

dy

=3x

2

−6xy−1

dx

dy

=

3(x

2

+1)

3x

2

−6xy−1

I hope it helped you

Answer 2

Answer:

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