Math, asked by hnjdm4gmail, 1 month ago

4) Identify the pair of corresponding angles, if ray BA Il ray EP and BC is transversal <(A) Z ABC and BPE () ZABP and Z PEF (C) ZABC and Z EPC (D) Z ABC and Z EPB B

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Answered by aashutosh72
1

Sum of interior angles x & y is 180

Sum of interior angles x & y is 180 o

Sum of interior angles x & y is 180 o

Sum of interior angles x & y is 180 o on same side of line

Sum of interior angles x & y is 180 o on same side of linex+y=180

Sum of interior angles x & y is 180 o on same side of linex+y=180 o

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x +

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o ∠PSR=180−

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o ∠PSR=180− 2

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o ∠PSR=180− 21

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o ∠PSR=180− 21 (x+y)

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o ∠PSR=180− 21 (x+y)From (i) x+y=180

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o ∠PSR=180− 21 (x+y)From (i) x+y=180∠PSR=90

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o ∠PSR=180− 21 (x+y)From (i) x+y=180∠PSR=90 o

Sum of interior angles x & y is 180 o on same side of linex+y=180 o …………(i)In triangle PSR sum of angle is 180 o 2x + 2y +∠PSR=180 o ∠PSR=180− 21 (x+y)From (i) x+y=180∠PSR=90 o .

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