Question

4. If 1 is a zero of polynomial p(x) = ax^2 - 3 (a - 1) -1, then find the value of a.

Answer 1

Answer:

x=1

p (x)=0

0=a (1)^2-3 (a-1) -1

0=a-3a+3-1

-2a= -2

a=1

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