Question

4
If 13 sin 0 = 12, then the value of cosec 0 is
(A)12/5
(B)13/5
(C)12/13
(D)13/12`​

Answer 1

Answer:

Step-by-step explanation:

13 sin∅ = 12

=> sin∅ = 12/13

=> cosec∅ = 13/12

formula used ;

\sin( \alpha )  =  \frac{1}{ \csc( \alpha ) }

Answer 2

Answer:

(D)13/12 is the correct option

Step by step explanation :

Given

13 × sin0 =12

So, sin0= 12/13

cosec(theta) = 1/sin(theta)

So cosec(0)= 1/sin(0)

cosec(0)=1/12/13

Therefore cosec(0)= 13/12

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