Question

4.
If 150 gram ice at 0°C is mixed with 10 gram
steam at 100°C then final temperature of
composition under ideal condition is
(1) Less than 0°C (2) 0°C
(3) 10°C
(4) 28°C​

Answer 1

Answer:

Final temperature of the mixture will be 0 degree C

Explanation:

150 gram ice at 0 degree C is mixed with 10 gram of steam at 100 degree C

so we know that ice will absorb the heat while steam will give the heat to the ice

So here we will have

$Q_1 = mL_f + ms\Delta T$

$Q_2 = m'L_v + m's\Delta T'$

now we know

$Q_1 = Q_2$

$150(80) + 150(1)(T - 0) = 10(540) + 10(1)(100 - T)$

$12000 + 150 T = 5400 + 1000 - 10 T$

$T < 0$

which is not possible and it shows that complete ice will not melt and it remains ice in the system

So final temperature is 0 degree C

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Topic : Calorimetery

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