Question

4 If 2 is a zero of polynomial f(x) = ax -3a+1)x – 1,
then find the value of a.​

Answer 1

Answer:

f(x)=ax-3(0-1)x-1

f(2)=2a+3*2-1

2a+6-1=0

2a+5=0  

2a=-5

a=-5/2

Answer 2

Answer: a = 1/4

Step by Step explanation:

Given polynomial: f(x) = ax-3ax+x-1

Zero of this polynomial = 2

If 2 is written in place of x, we get

f(2) = 2a-6a+2-1

f(2) = -4a + 1

-4a+1=0 [since 2 is the zero of this polynomial, the remainder is 0.]

-4a = -1

a = -1/-4 [minus get cancelled]

a = 1/4