4. If 7y + ky + 10 = (y + 5) (7y+2), then find the value of k.
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Answer:
7y+ky+10=(y+5)(7 y+2)
=7y+ky+10=7y^2+2y+35y+10
0r,7y^2+37y-7y-ky=0
or,7y^2+30y-ky=0
or,y(7y+30-k)=0
0r,7y+30-k=0
then, k=7y+30
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