Question

4) If A(5,4), B (-3,-2) and C (1-8) are the vertices of a A ABC. Segment
AD is median. Find the length of seg AD:​

Answer 1

Answer:

$\bf AD =3\sqrt{13} \ unit$

Step-by-step explanation:

In the figure AD is a median

So D is mid point of BC

Thus Coordinates of D are

{ (-3+1)/2, (-2-8)/2}

Or (-2/2,-10/2)

Or D( -1,-5)

Thus

$AD=\sqrt{(5-(-1))^2+(4-(-5))^2} \\\\=\sqrt{(5+1)^2+(4+5)^2} \\\\=\sqrt{6^2+9^2} \\\\=\sqrt{36+81} \\\\=\sqrt{117} \\\\\bf AD =3\sqrt{13} \ unit$