Question

4. If a and b are the roots of the equation 3x2 -6x +4 = 0, find the value of a2 + b2

Answer 1

a and b are the roots of 3x² - 6x + 4 = 0
sum of roots = - coefficient of x/coefficient of x²
a + b = -(-6)/3 = 2 -----(1)
product of roots =constant/coefficient of x²
ab = 4/3 ------(2)

Now, a² + b² = (a + b)² - 2ab
= (2)² - 2 × 4/3 [from question (1) and (2), ]
= 4 - 8/3 = (12 - 8)/3 = 4/3

Hence, a² + b² = 4/3

Answer 2

HELLO DEAR,

given, a AND b are the roots of the Equation,
3x² - 6x + 4 = 0,
where, a' = 3 , b' = -6 , c' = 4

a + b = -(b/a)

a + b = 6/3 = 2

a*b = c/a

a*b = 4/3

we know,

(a² + b²) = (a + b)² - 2ab

(a² + b²) = (2)² - 2*4/3

(a² + b²) = (12 - 8)/3

(a² + b²) = 4/3

I HOPE ITS HELP YOU DEAR,
THANKS