Question

4. If a.,ß are the zeroes of the polynomial x2 + x + 2 the
find the value of 20ß.​

Answer 1

Answer:

40

Step-by-step explanation:

x2 + x + 2

zeros a , b

a+b=(-1/1)=-1

ab=2/1=2

(a+b)square=(-1)square

a square + 2ab + b square=1

a square -2ab + b square+ 4ab=1

(a-b) square+4ab=1

(a-b) square+4×2=1

(a-b) square=1+8

(a-b) square=9

(a-b)=3

now

a+b= -1

a-b=3

by adding both wevget

2a=2

a=1

and

a+b= -1

1+b=-1

b = -1-1

b = -2

20b=20×(-2)

20b=-40

hence the answer