Math, asked by myra3360, 7 months ago

4. If a+b=6 and ab = 8. evaluate (i) a^2+b^2 and (i) - a-b​

Answers

Answered by varad032005
0

Answer:

Step-by-step explanation:

a+b=6  , ab=8

(i) a² +b² = (a+b)² -2ab

    a²+b²  = (6)² -2*8

 a²+b² =36-16

           =20

(ii)-a-b = -(a+b) = -(6) = -6

Answered by satyamtripathi62032
0

Answer:

i) 20 ii) 2

Step-by-step explanation:

I) ( a+b)^2 = a^2+b^2+2ab.

36= a^2+b^2+2×8. a^2+b^2= 20

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