4. If a+b+c=0 then (a + b + c) is
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Step-by-step explanation:
Since, a³ + b³ + c³ = 3abc = (a + b + c)(a² + b² + c² — bc - ca- ab)
Given, a + b + c = 0
-b³ + c³
.. a³ + b³ + c³ =
3abc = 0
= 3abc
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