| 4. If a car covers 2/5 of the total distance with v,
speed and 3/5" distance with V, then average
speed is
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Answer:
5vV/2v+3V
Explanation:
take the two time taken as t₁ and t₂
t₁=s/v₁=2/5v₁
t₂=s/v₂=3/5v₂
avg.speed=total distance/total time
=(2/5+3/5)/2/5v₁+3/5v₂
by simplification,we get,
5v₁v₂/2v₁+3v₂
here,
v₁ is v and v₂ is on the basis of your question
hope it helped and pls mark me as brainliest:)
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