Question

| 4. If a car covers 2/5" of the total distance with V
speed and 3/5 distance with v, then average
speed is​

Answer 1

Answer:

5vV/2V+3Vv

Explanation:

take the two time taken as t₁ and t₂

t₁=s/v₁=2/5v₁

t₂=s/v₂=3/5v₂

avg.speed=total distance/total time

               =(2/5+3/5)/2/5v₁+3/5v₂

by simplification,we get,

5v₁v₂/2v₁+3v₂

here,

v₁ is V and v₂ is v on the basis of your question

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