4. If AB = 12 cm, BC = 16 cm and AB is perpendicular
to BC, then find the radius of the circle passing
throught the points A, B and C.
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Step-by-step explanation:
In ABC AC = √(BC^2 + AB^2) = √(16^2 + 12^2)
= √(256+144) = √400 = 20cm
The line segment AC is the diameter of the circle
so , the length of the radius = 20÷2 = 10cm
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