4.
If alpha and Beta zeros of a polynomial x² + 6x + 9, then form a quadratic polynomial
whose zeroes are - a and - B.
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Step-by-step explanation:
The roots of the equation are:
x² + 6x + 9 = 0
=> x² + 2×3× x + 3² = 0
=> (x+3)² = 0
=> x = -3
Hence, both the roots of the equation are -3
Therefore,
-Alpha = -(-3) = 3 = -Beta
A polynomial whose roots are -Alpha and -Beta
= (x - 3)(x - 3) = (x-3)²= x² - 6x + 9
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