4. If c = 3ā – 2 b then prove that [ a b c]= 0
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Answered by
1
Answer:
152
65230Step-by-step explanation:
Answered by
1
Step-by-step explanation:
Given c = 3ā - 26
Prove that abc = 0
6 x 60 lf in a scalar triple product, two vectors are equal, then the secalar triple product is zero.
L.H.S= = [abe
- a ( b × c ) X
a (b b× (3a − 2b))
= abx
= à 3ā x 6. 5 x 5) 26
=
a(30 X 5-0)
= 2ā × ā × b =
= 2x0x6
=
0
Hence Proved
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