Question

4. If difference of two numbers is 4 and difference of their squares is 80. Then find the numbers?​

Answer 1

QUESTION:

If difference of two numbers is 4 and difference of their squares is 80. Then find the numbers?

ANSWER:

LET THE TWO NUMBERS BE X AND Y

X - Y = 4 (GIVEN)

X = 4 + Y ----(i)

GIVEN,

$\\ \\ \\ difference \: \: of \: \: the \: \: numbers \: \\ = {x}^{2} - {y}^{2} = 80\\ \\ \\ ( {4 + y)}^{2} - {y}^{2} = 80 \\ \\ \\ 16 + {y}^{2} - {y}^{2} + 8y = 80 \\ \\ \\ 8y = 80 - 16 \\ \\ \\ 8y = 64 \\ \\ \\ y = 8 \\ \\ \\ putting \: \: y \: in \: \: equation \: \: (i) \\ \\ \\ x = 4 + y = 4 + 8 = 12 \: \: (answer)$

Answer 2

Answer:

Note: This type of question is solved in a very limited method. The above method is a very good method to solve such questions in which there will be less chances of doubt and errors. Here we have used the area formula for triangles based on Heron’s method.Note: This type of question is solved in a very limited method. The above method is a very good method to solve such questions in which there will be less chances of doubt and errors. Here we have used the area formula for triangles based on Heron’s method.Note: This type of question is solved in a very limited method. The above method is a very good method to solve such questions in which there will be less chances of doubt and errors. Here we have used the area formula for triangles based on Heron’s method.Note: This type of question is solved in a very limited method. The above method is a very good method to solve such questions in which there will be less chances of doubt and errors. Here we have used the area formula for triangles based on Heron’s method.8