Question

4) If is the wavelength of light used in Young's double-slit experiment, the path difference for a phase difference of 117 rad is a) 23 2 b) 112 (119 d) 23 2​

Answer 1

Answer:

Explanation:

I  

′

 

=I  

1

​

+I  

2

​

+2  

I  

1

​

I  

2

​

 

​

cosθ

Phase difference is given by:

ϕ=2π×  

λ

path difference

​

 

ϕ=2π×  

λ

λ

​

 

=2π

So, the new intensity can be obtained as: ⇒I  

′

 

=4I  

1

​

 

given I  

′

 

=K,I  

1

​

=K/4,path difference=λ/3

phase difference is 2π×1/3

Hence, I=I  

1

​

+I  

2

​

+2  

I  

1

​

I  

2

​

 

​

cos2π/3

⇒I=I  

1

​

=K/4