Question

4.If n(U)=60 n(A')=24 n(B')=18 n(A'nn B')=6 then n(A nn B) is: (a) 24 (b) 54 (c) 36 (d) 42​

Answer 1

Answer:

n(AUB) = n(U) - n(AUB)’

n(AUB) = 60 - 10

= 50

Now,

n(AUB) = n(A) + n(B) - n(A∩B)

so,

n(A∩B) = n(A) + n(B) - n(AUB)

= 35 + 24 - 50

= 9 is your answer…..

Answer 2

solution

N(U)= 60

N(U)= 60N(AUB)'=10

N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'

N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10

N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10=50

N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10=50So N(A intersection B)= N(A)+N(B) - N (AUB)

N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10=50So N(A intersection B)= N(A)+N(B) - N (AUB)= 35+24-50

N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10=50So N(A intersection B)= N(A)+N(B) - N (AUB)= 35+24-50=9

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