Math, asked by sah706637, 7 months ago

4. If p= -2,9=-1 and r = 3, find the value of:
(a) p²+q²-r²
(b) 2p² - q² + 3r²
(d) p² +q³ +r³ +3 pqr (e) 3p²q + 5 pq² +2 pqr
(c) p-q-r
(f) p⁴ +q⁴ - r⁴​

Answers

Answered by pavanichinnuh
2

Answer:

where is Q value pls tell

Answered by asb333
2

c)p-q-r

 =  (- 2 )-1  + 3 \\   = 0 \\

f)p^4 +q^4-r^4

 =  { (- 2)}^{4}    + ( - 1)^{4}   - (3)^{4} \\   = 16 + 1 - 81  \\  = 17 - 81 \\  =  - 64

e)

 = 3  \times { (- 2)}^{2}  \times ( - 1) + 5( - 2) ( - 1) ^{2}  + 2( - 2)(3) \\  =  - 12  - 10 - 12 \\  =  - 34

Hope this helps

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