Question

4. If p(x) = x - 3x2 + 2x, find p(0), p(1), p(2). What do you conclude?​

Answer 1

Answer:

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⏩ ⒶⓃⓈⓌⒺⓇ ⏪

GIVEN :

If p(x) = x - 3x^2 + 2x, find p(0), p(1), p(2). What do you conclude?

SOLUTION :

➙ p(x) = x - 3x^2 + 2x

☛ p(x) = p(0)

➡ p(0) = 3 (0) ^2 + 2 (0)

➡ p(0) = 3 (0) + 0

➡ p(0) = 3 + 0

➡ p(0) = 3

⟹ p(0) = 3

☛ p(x) = p(1)

➡ p(1) = 3 (1) ^2 + 2(1)

➡ p(1) = 3 (1) +2

➡ p(1) = 3 + 2

➡ p(1) = 5

⟹ p(1) = 5

☛ p(x) = p(2)

➡ p(2) = 3 (2) ^2 + 2(2)

➡ p(2) = 3(4) +4

➡ p(2) = 12 + 4

➡ p(2) = 16

⟹ p(2) = 16

THEREFORE, THE VALUE OF

"p(0) = 3" , "p(1) = 5" & "p(2) = 16"

BUT THEY ARE NOT EQUAL..

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Step-by-step explanation:

℘ℓḙᾰṧḙ ՊᾰԻк Պḙ ᾰṧ ♭Իᾰ!ℵℓ!ḙṧт ✌✌✌