Chemistry, asked by amansinghjatt1271, 9 months ago

-4. If pentane is used as fuel in fuel cell, then its Gibbs free energyis expressed as (E°= 1.23 V)a) 4Gº = -32F/(1.23) b) AG° = -8 F/(1.23)FEc) AG° = -4F/(1.23) d) AG° = -8 F/(1.23)​

Answers

Answered by turkshehreen000
0

Answer:

ans c

Explanation:

vf=8( 2*2)

vf=32

∆G°= -nFE° cell

=

-32 n (1.23)

∆G°= -nFE

=( -4)F 1.23

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