-4. If pentane is used as fuel in fuel cell, then its Gibbs free energyis expressed as (E°= 1.23 V)a) 4Gº = -32F/(1.23) b) AG° = -8 F/(1.23)FEc) AG° = -4F/(1.23) d) AG° = -8 F/(1.23)
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Answer:
ans c
Explanation:
vf=8( 2*2)
vf=32
∆G°= -nFE° cell
=
-32 n (1.23)
∆G°= -nFE
=( -4)F 1.23
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