Question

4. If Q1, Q2, az (az > 0) are three successive terms of a GP with common ratio r, the value of r for which a3 > 4a2 - 3a1 holds is given by :
(a) 1<r<3
(b) -3<r<-1
(c) r > 3 or r < 1
(d) none of these​

Answer 1

$\huge{\boxed{\overline{\underline{\mathfrak{\fcolorbox{cyan}{blue}{Answer}}}}}}$

=> r < 1. or r > 3

•Let a1,a2,a3 be first three consecutive term of GP having common ratio r.

• a2 = a1r and a3 = a1r²

Given that,

a3 > 4a2 - 3a1

=> a1r² > 4a1r - 3a1

=> r² > 4r - 3

=> (r - 1)(r - 3) > 0

=> r < 1. or r > 3

silentlover45.❤️

Answer 2

Answer:

$\implies$ options no (a) 1<r<3