Question

4. If sin 0 = 5, then 3 cos 0. sin (90 – 0) =​

Answer 1

Step-by-step explanation:

sin0 = 5

3cos0.sin(90-0)

3cos0.cos0 ......[sin(90-0)=cos0]

3cos^2 (0)

sin0 = 5

cos^2 0 = 1- sin^20

= 1- 25

= -24

3cos^2 (0)

3(-24)

-72