Question

4. If sin θ= 17/8 then tan θ is equal to a)15/17 b) 15/7 c) 15/8 d) 8/15​

Answer 1

Answer:

tanθ = 17/15

Step-by-step explanation:

sin θ = p/h , tanθ= p/b

p=17 , h= 8

using Pythagoras theorem

${h}^{2} = {p}^{2} + {b}^{2}$

${b} = \sqrt{ {h}^{2} - {p}^{2} }$

$b = \sqrt{17^{2} - {8}^{2} }$

$b = \sqrt{225}$

b = 15

Answer 2

Answer:

d)8/15

Step-by-step explanation:

Ok at first i didn't want to answer this. But seeing all others giving wrong answer, i decided to answer.

First of all, I think you have typed question wrong. Because sin theta = opposite side of angle/hypotenuse.

Hypotenuse is always greater than side. But in question, it is given sin theta = 17/8 where 8 is lesser than 17.

So, i think sin theta = 8/17.

Then, hypotenuse = 17, side = 8 and other side we need to find.

We have Pythagoras theorem which says,

(Hypotenuse)^2 = side ^2 + side ^2

So, 17^2 = side^2 + 8^2

So, 289 -64 = side ^2

So, side = 15.( this side is adjacent side to theta)

Now , tan theta = opp. side of theta/adjacent side of theta

So, tan theta = 8/15

So, option d is correct.

Hope it helps.

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Thank You