Question

4. If Sin (A+B) = 1, Cos (A-B)=✓3/2 ,0 degrees <A+B<90 degrees, A>B, find the value of A & B​

Answer 1

Answer:

A=60°

B=30°

Step-by-step explanation:

Sin(A+B)=1

so, A+B=90. (sin 90=1)

Cos(A-B)=√3/2

A-B=30. (cos 30=√3/2)

by elimination,

A=60°

B=30°