Question

4. If sinA=3/5 and A is acute
then tanA will be​

Answer 1

Answer:

sinA= P/H

3/5= P/H

P=3, H=5

B^2= H^2- P^2

B^2= 25-9

B^2= 16

B=4

Now, tanA= P/B

tanA= 3/4