Question

4. If the angles of a pentagon are in the ratio 7:8:11 :13 : 15
, find the angles.
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Answer 1

Answer:

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Step-by-step explanation:

From the question, it is given that, The angles of a pentagon are in the ratio 7: 8: 11: 13: 15  

We know that, Sum of measures of all interior angles of polygons =(2n−4)×90  

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Given, n=5

=((2×5)−4)×90  

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=(10−4)×90  

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=6×90  

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=540  

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Let us assume the angles of the pentagon be 7a,8a,11a,13a and 15a.

Then, 7a+8a+11a+13a+15a=540  

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54a =540  

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a =540/54

a =10  

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Therefore, the angles are 7a=7×10=70  

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8a=8×10=80  

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11a=11×10=110  

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13a=13×10=130  

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15a=15×10=150  

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Answer 2

Answer:

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