Question

4] If the area of rectangle is 15m and breadth is 10m. Find area of rectangle​

Answer 1

Area of triangle= 1/2x basex height

=1/2x15x10

= 30 sqcm

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Answer 2

Correct Question :

• If the length of rectangle is 15m and breadth is 10m. Find area of rectangle

Given :

• Length of Rectangle = 15m
• Breadth of Rectangle = 10m

To Find :

• Area of Rectangle

Solution :

✰ As we know that, Area of Rectangle is given by Length × Breadth . So Simply we will put the given values in the formula to find the area of Rectangle.

⠀⠀⠀

⠀⠀⟼⠀⠀Area of Rectangle = L × B

⠀⠀⟼⠀⠀Area of Rectangle = 15 × 10

⠀⠀⟼⠀⠀Area of Rectangle = 150m²

Thus Area of Rectangle is 150m²

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What is we need perimeter also ?

⠀⠀⟼⠀⠀Perimeter = 2(L + B)

⠀⠀⟼⠀⠀Perimeter = 2(15 + 10)

⠀⠀⟼⠀⠀Perimeter = 2 × 25

⠀⠀⟼⠀⠀Perimeter = 50m

Thus perimeter of Rectangle is 50m

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$\begin{gathered} \green{\boxed { \begin{array}{ |c|c| } \hline \\ \sf \blue{Perimeter \: of \: rectangle}& \sf \red{2(length + breadth)} \\ \\ \hline \\\blue{ \sf Area \: of \: rectangle}& \sf \red{length \times breadth}\\ \\ \hline \\ \sf\blue {Length \: of \: rectangle}& \sf \red{\dfrac{Area }{ Breadth}} \\ \\ \hline \\ \sf \blue{Breadth \: of \: rectangle}& \sf \red{ \dfrac{Area}{Length} }\\ \\ \hline \\ \sf \blue{Diagonal \: of \: rectangle}& \sf \red{\sqrt{ {length}^{2} + {breadth}^{2} }} \\ \\ \end{array}}}\end{gathered}$