Question

4. If the diagonal of the square is 42 cm, find its area.​

Answer 1

Answer:

Area of square =diagonal^2

=diagonal * diagonal

= 42 * 42

= 1764 cm ^2.

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Answer 2

Explanation:

Here, ABCD is a square.

Let AB=BC=CD=AD=a [ All sides of square are equal ]

⇒ AC=42cm [ Given ]

In right angled △ABC,

⇒ (AC)^2=(AB)^2+(BC)^2

[ By Pythagoras theorem ]

⇒ (42)^2=a^2+a^2

⇒ 1764=2a^2

⇒ a^2 =1764/2

=> a^2 = 882

⇒ Area of a square =a^2 = 882 cm^2 ANSWER