Question

4. If the difference of the roots of the quadratic equation x2 - ax + b = 0 is 1, then prove that
a2-4b = 1.​

Answer 1

Answer:

a2-4b = 1

Step-by-step explanation:

Let the two roots of the quadratic equation be p & q.

Now, According to the properties of quadratic equation we have,

p + q = -(-a) / 1 = a

& pq = b / 1 = b

Now, (p-q)2 = (p+q)2 -4pq

1 = a2 - 4b or a2 - 4b = 1