Question

4. If the lines 3x + (k – 1)y – 9 = 0 and 3x – 4y + 3k = 0 are coincident then find the value of k.​

Answer 1

Step-by-step explanation:

CONDITION FOR COINCIDING LINES:

$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$

Therefore,

$\frac{3}{3 } = \frac{k - 1}{ - 4} = \frac{ - 9}{3k}$

Hence,

$1 = \frac{k - 1}{ - 4} \\ - 4 = k - 1 \\ k = - 4 + 1 \\ k = - 3$

Hence, k = -3

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