Question

4. If the roots of equation (p= 4) x2 + 2(p-4)x+ 4 = 0 are equal then value of p is:
(a) 8
(b) -8
(c) 5
(d)-5​

Answer 1

Step-by-step explanation:

When roots of quadratic equations is equal

$({2(p - 4)})^{2} - 4 \times 4 \times 4 = 0 \\ 4 {(p - 4}) ^{2} = 64 \\ ( {p - 4)}^{2} = 16 \\ p - 4 = - 4 \: \: or \: 4 \\ p = 8 \: \: or \: \: 0 \\ answer \: is \: (a) \: 8$