Question

4. If the roots of the equation
$a {x}^{2} + bx + c = 0$
are in the ratio 3:5 then.
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Answer 1

Answer:

x=2a−b±b2−4ac

x=2a−b±D

d2=b2−4ac⇒d=±D

x=−2ab±2ad

x1=−2ab+2ad

x2=−2ab−2ad

Given,

x2x1=43

−(b+d)d−b=43

4(d−b)=3[−(b+d)]