Question

4.If the sum of four consecutive odd numbers is 56, find the four numbers.​

Answer 1

Answer:

hope my answer helps you..

Answer 2

Given :

• the sum of four consecutive odd numbers is 56

To find :

• the four numbers

Solution :

⇒ Let the consecutive odd numbers be :

• 2x + 1
• 2x + 3
• 2x + 5
• 2x + 7

⇒ Now, let's find.

= (2x + 1) + (2x + 3) + (2x + 5) + (2x + 7) = 56

= 2x + 1 + 2x + 3 + 2x + 5 + 2x + 7 = 56

= (2x + 2x + 2x + 2x) + (1 + 3 + 5 + 7) = 56

= (8x) + (16) = 56

= 8x + 16 = 56

= 8x = 56 - 16

= 8x = 40

= x = 40/8

= x = 5

⇒ Let's find the numbers.

→ 2x + 1

= 2 × 5 + 1

= 10 + 1 = 11

→ 2x + 3

= 2 × 5 + 3

= 10 + 3 = 13

→ 2x + 5

= 2 × 5 + 5

= 10 + 5 = 15

→ 2x + 7

= 2 × 5 + 7

= 10 + 7 = 17

• Therefore, the four numbers are 11, 13, 15, and 17.