4. If the the zeroes of the polynomial f(x) = x² – ax + (b+1) are 4 and -5, then
(a) a = 1, b = -19
(b) a= -1, b = -19
(c) a = 1, b = -21
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Answer:
b is the right answer mark as brainliest brother
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Case 1-
(4)²-4a+(b+1) =0
16-4a+b+1=0
4a-17=b ---1
Case 2-
(-5)²-(-5)a+(b+1) =0
25+5a+b+1=0
-26-5a=b
-26-5a=4a-17
-26+17=4a+5a
-9=9a
-1=a
So,
4a-17=b => 4(-1)-17=b =-21
a = - 1 and b = - 21
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