Question

4. if the two forces F, = 5 N
and F, = 3 N acting at points A and B of a rod pivoted
at a point o, such that OA = 2 m and OB = 4 m.
A
2m
4m
ok
F2=3N
F, 5N

Calculate :
(i) the moment of force F, about O.
(ii) the moment of force F, about O.
(iii) total moment of the two forces about O.
Y
monticlockwise)​

Answer 1

Answer:

GIVEN OA=2M AND OB =4M

MOMENTUM OF FORCE F1(=5N) AT A ABOUT THE POINT O= F1*OA

=5*2=10Nm

(ANTICLOCKWISE)

MOMENTUM OF FORCE F2(=3N)

AT B ABOUT THE POINT O= F2*OB

=3*4=12Nm