Question

4. If the volume of a right circular cone of height 9 cm is 48 T cm", find the diameter of its
base.​

Answer 1

Let r be the radius of the cone.

$= > volume = \frac{1}{3}\pi \: {r}^{2} h$

$= > 48 = \frac{1}{3} \times 3.14 \times {r}^{2} \times 9$

$= > {r}^{2} = \frac{48 \times 3}{3.14 \times 9} = \frac{144}{28.26} = 5.48$

$= > r = 2.34cm$

Diameter = 2r = 4.68cm

Hence, diameter of the right circular cone is 4.68cm.

Hope this answer helps you ^_^ !