Question

4. If the zeroes of the quadratic polynomial x2 + (a +1)x + b are 2 and -3, then
(a) a=-7,b=-1
(b) a= 5, b= -1
(c) a =2, b=-6
(d) a = 0,b= -6​

Answer 1

c

Step-by-step explanation:

alpha+beta=2-b/a

alpha ×beta = -3

2=-(a+1÷2)

4=-a-1

Answer 2

Answer:

Let, the one zero be alpha

and another zero be bita

alpha + bita = ‐b/a

2+(‐3) = ‐(a+1)/1

‐1 = ‐(a+1)

1 = a+1

a+1 = 1

a = 1‐1

a =0

alpha × bita = c/a

2(‐3) = b/1

‐6 = b

b= ‐6

so, a= 0 and b=‐6