Question

4: If Vcc= +18 V, voltage-divider resistor R, is 4.7 kO,
and R2 is 1500 Q, then the base bias voltage is
2485302595
8.77
4,35 V
2.9 V
0.77
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Answer 1

Answer:

The answer is 8.77 dear....

Answer 2

Answer:

4.35 V

Explanation:

Considering a BJT voltage divider configuration we observe that

Resistance R2 is  small, resulting in a small base current thus base voltage is obtained as follows

V B = V cc × $\frac{R2}{R1+R2}$

If Vcc= +18 V, voltage-divider resistor R, is 4700Q,

and R2 is 1500 Q, then the base bias voltage is

V B = 18 × $\frac{1500}{1500+4700}$

V B = 4.35 V