Question

4. If (x-a) isa factor of 4x² - mx-ha, prove that a = m+n/4

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Answer 1

Step-by-step explanation:

x-a=0

x=a

4x²-mx-na=0

4a²-ma-na=0

a(4a-m-n)=0

4a-m-n=0

4a=m+n

a=(m+n)/2

Answer 2

Step-by-step explanation:

•(x-a)=0

x= a

•p(x)=4(a)^2-mx-na

p(a)=4(a)^2-m(a)-na

0=4a-ma-na

0=a(4a-m-n)

0=4a-m-n

4a=m-n

a=m-n/4