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If x + y = 8 and xy = 3, find the values of
(ii) 3(x2 + y2) (iii) 5(x2 + y2) + 4(x - y).
(1) x-y
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Answer:(ii) 3(x2 + y2)= 3*2(x+y)
We know that X+Y is 8 so putting that value in the equation
6*8=48
Explanation: please mark it brainliest
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