Question

4. If x + y = p and xy =q, then the value of
1 1
will be
+
3
23
3
у​

Answer 1

$\huge \mathcal\colorbox{lightblue}{Hey...}$

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$\mathsf \red{ If \: x + y \: = p \: and \: xy =q, then \: the \: value \: of \: \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } }$

$\mathsf \blue{ \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } = {\frac{ {x}^{3} + {y}^{3} }{ {x}^{3} {y}^{3} } } } \\ \mathsf \blue{ = \frac{ {(x + y}^{3} - 3xy(x + y)}{ {xy}^{3} } } \\ \mathsf \blue{ = \frac{ {p}^{3} - 3qp}{ {q}^{3} } }$

Thanku...