4. If y=(cotx}sinx+(tan x)cos x the finf dydx
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Step-by-step explanation:
dy/dx=-csc²x(sinx) +cotx(cosx) + sec²x(cosx) +tanx(-sinx)
dy/dx=-1/sinx+cos²x/sinx+1/cosx-sin²x/cosx
dy/dx=cos²x-1/sinx+1-sin²x/cosx
dy/dx=-sin²x/sinx+cos²x/cosx
dy/dx=cosx-sinx
longest method hahahaa just for timepass
short one
simplify 1st
y=(cotx)sinx+(tan x)cos x
y=cosx+sinx
dy/dx=cosx-sinx
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