Question

4. If z1=5+ i and z2=2 + 2i then find z1/z2 how to find it plss..help me..!

Answer 1

See the attachment for detail solution
Hope it will help you

Answer 2

Solution :

Now,

$\frac{ z_1 }{ z_2 } \\ \\ = \frac{5 + i}{2 + 2i} \\ \\ = \frac{(5 + i)(2 - 2i)}{(2 + 2i)(2 - 2i)} \\ \\ = \frac{10 - 10i + 2i - 2 {i}^{2} }{4 - 4 {i}^{2} } \\ \\ = \frac{10 - 8i + 2}{4 + 4} \: \: (since \: \: i = \sqrt{ - 1} ) \\ \\ = \frac{12 - 8i}{8} \\ \\ = \frac{12}{8} - \frac{8}{8} i \\ \\ = \frac{3}{2} - i \\ \\ i \: \: is \: \: the \: \: square \: \: root \: \: of \: \: ( - 1)$

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