Question

4. Ifa and Bare zeroes of the polynomial p(x)=x² + ax+b
+ B, then a polynomial whose zeroes are 1/alpha,1/beta is given by
(a) x² + bx +a
(b) x² - ax + b
(c) bx² + ax + 1
(d) ax² + x + b​

Answer 1

Answer:

x² - ax + b is the answer...