Question

4. Imagine a circuit with a 1.5V battery and one bulb. Imagine a similar circuit
with a 3V battery and two bulbs. Which has the brightest bulbs?
a) The circuit with a 1.5V battery and one bulb
b) The circuit with a 3V battery and two bulbs
c) The bulbs in both circuits are of similar brightness levels

Answer 1

Answer:

Option C

Explanation:

As in option 1 the bulb has 1.5 V and in option B 3V is divided into two

Answer 2

The bulbs in both circuits are of similar brightness levels.

• In the first circuit, the circuit's total resistance due to the bulb is "R."
• And the net voltage for the bulb in the first circuit is 1.5V. So, the current in the bulb of the first circuit is I = 1.5V/R.
• The net resistance due to the two bulbs in the second circuit is "2R."
• And the net voltage in the circuit is 3V. So, the current passing through both the bulbs of the second circuit is I' = 3V/2R = 1.5V/R.
• The value of current through the bulbs is equal in both circuits.
• The bulb with a higher value of power will shine brighter.                    And the power of the bulb = $I^{2} R$
• As found, the value of current and resistance of all the bulbs is the same. All bulbs will shine at a similar level.
• Hence the correct answer is option C).